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ollyno1uk
Joined: 23 Jul 2006
Posts: 2
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 Posted: Sun Jul 23, 2006 2:54 am getting information without using submit |
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I am trying to use this code to show stock levels in my shop. it checks another website for stock levels when the submit button is pressed. is there a way that i can bypass the submit button and just have the stock level showing when the page loads? here is an example of the code i'm using at the moment
| Code: |
<form method="post" action="https://www.webpage.com/gateway/get_prod_info.asp">
<input type="hidden" name="sku" value="GLAC51">
<input type="hidden" name="return_string" value="[stock_level] on hand, costing [rrp]">
<input type="hidden" name="reseller_id" value="useratcompany.com">
<input type="hidden" name="reseller_pass" value="pass">
<input type="submit" name="submit" value="submit">
</form> |
Thanks for your help |
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Corey Bryant
Site Admin
Joined: 15 May 2004
Posts: 8267
Location: Castle Rock CO USA
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| Posted: Sun Jul 23, 2006 5:42 am |
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If that stock level is in the database couldn't you just pull that number from the database when the page is generated?
_________________
Corey
Loud Info | Loud Worx | Merchant Account Blog |
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ollyno1uk
Joined: 23 Jul 2006
Posts: 2
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| Posted: Sun Jul 23, 2006 8:50 am |
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| This is an external database but this is exactly what I would like to do. |
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degsy
Joined: 23 Feb 2005
Posts: 2440
Location: North East, UK
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| Posted: Mon Jul 24, 2006 10:27 am |
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You can use javascript to submit a form onload. This is bad practice as client side javascript can be disabled.
A better option would be to use server side XMLHTTP
Here is an example of posting to a script
| Code: |
<%@LANGUAGE="VBSCRIPT" CODEPAGE="1252"%>
<%
If Len(Request.Form) > 0 Then
dim strResponse,destURL,strContent
destURL = "http://domain.com/xmlhttp_post_script.asp"
Response.Write destURL
'Construct the Post Data
strContent = strContent & "name=" & server.URLencode(Request.Form("name"))
strContent = strContent & "&pass=" & server.URLencode(Request.Form("pass"))
'Construct the useragent and send
set http_obj=server.CreateObject("MSXML2.ServerXMLHTTP")
http_obj.Open "POST", destURL , false
http_obj.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
http_obj.send(strContent)
'Grab the response
strResponse = http_obj.ResponseText
set http_obj=nothing
Response.Write "Form sent"
response.write( strResponse )
End If
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Untitled Document</title>
</head>
<body>
<form name="form1" method="post" action="">
<p>Name:
<input name="name" type="text" value="joe">
</p>
<p>Pass:
<input name="pass" type="password" value="1234">
</p>
<p>
<input type="submit" name="Submit" value="Submit">
</p>
</form>
</body>
</html>
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